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59 lines
1.6 KiB
Python
59 lines
1.6 KiB
Python
#!/usr/bin/env python
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# coding=utf-8
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##################################################################################
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# Leetcode 35 搜索插入位置
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#
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# 给定一个排序数组和一个目标值，在数组中找到目标值，并返回其索引。如果目标值不存在于数组中，返回它将会被按顺序插入的位置。
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# 你可以假设数组中无重复元素。
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#
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# 示例 1:
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# 输入: [1,3,5,6], 5
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# 输出: 2
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#
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# 示例 2:
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# 输入: [1,3,5,6], 2
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# 输出: 1
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#
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# 示例 3:
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# 输入: [1,3,5,6], 7
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# 输出: 4
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#
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# 示例 4:
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# 输入: [1,3,5,6], 0
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# 输出: 0
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##################################################################################
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class Solution:
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def searchInsert(self, nums, target):
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"""
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:type nums: List[int]
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:type target: int
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:rtype int
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(knowledge)
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思路：
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1. 用二分查找试图找到目标值；
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2. 找到则返回其索引，没找到则返回其可能被插入的位置
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"""
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left, right = 0, len(nums) - 1
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while left + 1 < right:
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mid = left + (right - left) // 2
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if nums[mid] == target:
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return mid
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if nums[mid] > target:
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right = mid
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else:
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left = mid
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return left if nums[left] >= target else (right if nums[right] >= target else right + 1)
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if __name__ == '__main__':
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solution = Solution()
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print(solution.searchInsert([1, 3, 5, 6], 5), "= 2")
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print(solution.searchInsert([1, 3, 5, 6], 2), "= 1")
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print(solution.searchInsert([1, 3, 5, 6], 7), "= 4")
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print(solution.searchInsert([1, 3, 5, 6], 0), "= 0")
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