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algorithm-review/chapter9/7_binary-tree-preorder-traversal.py
T
2020-06-21 21:29:26 +08:00

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Python

#!/usr/bin/env python
# coding=utf-8
#######################################################################################
# Leetcode 144 二叉树的前序遍历
#
# 给定一个二叉树,返回它的前序遍历。
#
# 示例:
# 输入: [1,null,2,3]
# 1
# \
# 2
# /
# 3
#
# 输出: [1,2,3]
#
# 进阶: 递归算法很简单,你可以通过迭代算法完成吗?
#######################################################################################
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None
def __repr__(self):
if self:
return "{}->{}->{}".format(self.val, repr(self.left), repr(self.right))
class Solution:
def preorderTraversal(self, root):
"""
:type root: TreeNode
:rtype List[int]
(knowledge)
思路:
1. 使用一个列表记录遍历过的值;
2. 每次先将当前节点的值加入结果集,然后递归遍历左右子树;
"""
def _preorderTraversal(root, result):
if not root:
return result
result.append(root.val)
_preorderTraversal(root.left, result)
_preorderTraversal(root.right, result)
return result
result = []
return _preorderTraversal(root, result)